4.9x^2+38x+2=0

Solution for 4.9x^2+38x+2=0 equation:

4.9x^2+38x+2=0

a = 4.9; b = 38; c = +2;
Δ = b2-4ac
Δ = 382-4·4.9·2
Δ = 1404.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-\sqrt{1404.8}}{2*4.9}=\frac{-38-\sqrt{1404.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+\sqrt{1404.8}}{2*4.9}=\frac{-38+\sqrt{1404.8}}{9.8}
$